5x^2+35x=40

Solution for 5x^2+35x=40 equation:

5x^2+35x=40

We move all terms to the left:

5x^2+35x-(40)=0

a = 5; b = 35; c = -40;
Δ = b2-4ac
Δ = 352-4·5·(-40)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-45}{2*5}=\frac{-80}{10}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+45}{2*5}=\frac{10}{10}
=1
$